Question

Level-2
The age of a father is 25 years more than his son's age. The product of their ages is 84 in years. What will
be son's age in years, after 10 years?
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Answer 1

age of son =X

age of father =X+25

product of age= 84

X(X+25)=84

X^2+25X=84

X^2+25X-84=0

solving this we get ,X=3

.: age of son in year =3

age of father in year =X+25

=3+25

=28

:. age of son after 10 years =3+10=13

age of father after 10 years=38