Question

Level 3 ques no. 11 pls

Answer 1

hello,
given equation is (x+2)/4-[(11-x)/2-3/8]=(3x-4)/8
⇒(x+2)/4-[4(11-x)-3]/8=(3x-4)/8
⇒(x+2)/4-[44-4x-3]/8=(3x-4)/8
⇒(x+2)/4-[41-4x]/8=(3x-4)/8
multiply whole equation by 8
⇒8(x+2)/4-8[41-4x]/8=8(3x-4)/8
⇒2x+4-[41-4x]=3x-4
opening bracket
⇒2x+4-41+4x=3x-4
⇒6x-37=3x-4
6x-3x=-4+37
3x=33
x=11
hope this helps,if u like it please mark it as brainliest

Answer 2

This is your answer hope it may helps you !!!!