lf -1/3 is one of the zero of 9x2-kx-5 then find k
Answers
Answer:
given : 9x^2 - kx - 5 and -1/3 is one of zero
so, it is zero of polynomial
then
9( -1/3 )^2 - k( -1/3 ) - 5 = 0
9( 1/9 ) + k/3 - 5 = 0
1 + k/3 -5 = 0
k/3 = 4
K = 12
Given : -1/3 is one of the zeroes of polynomial 9x^2-kx-5
To Find : value of k
Solution:
-1/3 is one of the zeroes of polynomial 9x²-kx-5
that means substituting x = - 1/3 will lead polynomial to zero
Hence
9(-1/3)² - k(-1/3) - 5 = 0
=> 1 + k/3 - 5 = 0
=> k/3 = 4
=> k = 12
value of k = 12
9x^2-12x-5
=9x² -15x + 3x - 5
= 3x(3x -5 ) + 1(3x - 5)
= (3x + 1)(3x - 5)
x = -1/3 , 5/3
Verified
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