Question

lf -1 is a zero of the polynomial p(x)=ax³-x²+x+4,then find the value of 'a'​

Answer 1

Answer:

So, X= -1

P(-1) =a(-1)^3 -(-1)^2 + (-1) +4

=a-1 +1 -1 +4

= a-1 +4

a+1= 4

a= 4-1

a= 3

Answer 2

Step-by-step explanation:

-1 is a zero of the polynomial given means -1 is one of the root of this polynomial.

therefore. ax^3-x^2+X+4=0

a(-1)^3-(-1)^2+(-1)+4=0

-a-1-1+4=0

-a+2=0

a= 2

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