Question

lf (2, k) is One solution of equation x+y+2=0, then what is the value of k? anes​

Answer 1

Answer:

Hence, the value of k is -4

Step-by-step explanation:

Given : Equation is = x + y + 2 = 0 ………(1)

(2, k) is one solution of the above given equation .

To find: The value of k.

Solution:

It is given that (2,k) is a solution of the equation then it must satisfy the given equation.

Here, x = 2 and y = k

Now put these values in equation (1), we get:

x + y + 2 = 0

2 + k + 2 = 0

4 + k = 0

k = 0 - 4

k = - 4

Hence, the value of k is -4

Answer 2

Answer:

Value of k is -4

Step-by-step explanation:

Given :

Equation is = x + y + 2 = 0  

(2, k) is solution of the given equation .

To find :

Value of k

Solution :

If any point is a solution of the equation then it must satisfy the given equation.

Here, x = 2 and y = k

Now substituting these values in equation, we get,

x + y + 2 = 0

=> 2 + k + 2 = 0

=> 4 + k = 0

=> k = 0 - 4

=> k = - 4

∴ The value of k is -4

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