Question

lf 3 tan A=4, then find sin A and cosA​

Answer 1

Answer:

sin A = 3/5 and cosA = 4/5

......

Answer 2

Answer:

tanA=4/3=p/b

from a p.g.t

h^2=p^2+b^2

h^2=4^2+3^2

h^2=16+9

h^2=25

h=√25

h=5

sinA=p/h=4/5

cosA=b/h=3/5