Question

lf 4/5a,2are three consecutive terms of an A.P., then find the value of a​

Answer 1

Answer:

4/5 , a, 2 are in ap

then a-4/5=2-a

2a=2 + 4/5

a=1 + 2/5 = 7/5 answer

Answer 2

$\Huge\bigstar\:\tt\underline\red{:ANSWER:}$

$\huge\mathscr\green{Given:-}$

${\implies}$$\frac{4}{5}$,${a,2......}$.

$\huge\mathscr\red{:First Term:}$

${\implies}$${a= -\frac{4}{5}}$

$\large\mathscr\blue{:Common difference:}$

${\implies}$${d=a2-a1=a3-a2}$

${\implies}$${a-\frac{4}{5}=2-a}$

${\implies}$${a+a=\frac{2}{1}+}$$\frac{4}{5}$

${\implies}$${2a=\frac{10+4}{5}}$

${\implies}$${a=\frac{14}{5×2}}$

${\huge{\boxed{\purple{\therefore{a=\frac{7}{5}}}}}}$.