Question

lf 4 tan α= 3, then the value of (4sinα-cosα/4sinα+cosα)is equal to​

Answer 1

Answer:

i

= 3/5 cosα=4/5

Then, (4sinα-4cosα)÷(4sinα+cosα-1)

= (4×3/5-4×4/5)÷(4×3/5+4/5-5/5)

= (12/5-16/5)÷(12/5-1/5)

= (-4/5)÷(11/5)

=-4/5×5/11

=-4/11

Answer 2

Answer:

See this image answer is 1/1.5