Question

lf 4 tanfl = 3, then the value of (fl"-ros a\

-- \+ rinffiilrf is egual to​

Answer 1

Answer:

question is wrong

Step-by-step explanation:

because yeh kya hai

Answer 2

The value of $5\sin \theta-12\cos \theta= -45$

Step-by-step explanation:

We have,

$\tan \theta=\dfrac{3}{4}$

To find, $5\sin \theta-12\cos \theta=?$

∴ $\tan \theta=\dfrac{3}{4}=\dfrac{p}{b}$

$h=\sqrt{3^{2}+4^{2}} =\sqrt{9+16}$

$=\sqrt{25}=5$

Where, b = base, p = perpendicular and h = hypotaneous

∴ $\sin \theta=\dfrac{p}{h}=\dfrac{3}{5}$ and

$\cos \theta=\dfrac{b}{h}=\dfrac{4}{5}$

∴ $5\sin \theta-12\cos \theta$

$=5\times \dfrac{3}{5}-12\times \dfrac{4}{5}$

= 3 - 48

= - 45

Hence, the value of $5\sin \theta-12\cos \theta= -45$