Question

lf a=1and b=-2and c=3 then tind the value of a2+b2+c2+ab+bc+ca​

Answer 1

Answer:

a^2+b^2+c^2+ab+bc+ca= (a+b+c)^2

1^2-2^2+3^2+1×(-2)-2×3+3×1

(1-2+3)^2 is the answer

Answer 2

Hey mate here your answet

a2+b2+c2+ab+bc+ca. find?

a=1,b=-2,c=3

1(2)+-2(2)+3(3)+1(2)+2(3)+3(1)

2-4+9+2+6+3

-2+9+2+6+3

-7+2+6+3

-9+6+3

-3+3

0

so,the answer is "0"

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