Question

lf A= {3, 5, 7, 9, 11}, B={7, 9, 11, 13 }, C={11, 13, 15} and D={15, 17 }; find $A \cap ( B \cup C )$

Answer 1

we know, if two sets A and B are given then, intersection of A and B is the set of all distinct elements that are in both A and B. it is denoted by $A\cap B$ or $B\cap A$. in figure, shaded region indicates $A\cap B$.
and A union B is the set of all distinct elements that are in Both A or B. it is denoted by $A\cup B$. in 2nd figure, it is clearly shown.

now come to the question,
here given, A= {3, 5, 7, 9, 11}, B={7, 9, 11, 13 }, C={11, 13, 15} and D={15, 17 }.
we have to find $A\cap(B\cup C)$
first we have to find $B\cup C$
so, $B\cup C$ = {7, 9, 11, 13} U {11, 13, 15}
= { 7, 9, 11, 13, 15}
now, $A\cap(B\cup C)$ = {3, 4, 7, 9, 11} $\cap$ {7, 9, 11, 13, 15}
= {7, 9, 11}

Answer 2

Answer:

A cap ( BUC ) = { 7,9,11 }

Step-by-step explanation:

Given A = { 3 ,5,7,9,11 }

B = { 7,9,11,13 }

C = { 11,13,15 }

A cap ( B U C )

= A cap ( { 7,9,11,13 } U { 11,13,15 })

= A cap { 7,9,11,13,15 }

= { 3,5,7,9,11 } cap { 7,9,11,13,15 }

= { 7,9,11 }

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Answer 3

Answer:

A cap ( BUC ) = { 7,9,11 }

Step-by-step explanation:

Given A = { 3 ,5,7,9,11 }

B = { 7,9,11,13 }

C = { 11,13,15 }

A cap ( B U C )

= A cap ( { 7,9,11,13 } U { 11,13,15 })

= A cap { 7,9,11,13,15 }

= { 3,5,7,9,11 } cap { 7,9,11,13,15 }

= { 7,9,11 }

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