lf A= {3, 6, 9, 12, 15, 18, 21} , B={4, 8, 12, 16, 20 }, C={2, 4, 6, 8, 10, 12, 14, 16} D={5, 10, 15, 20}; Find C - B
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concept :- A - B shows the relative complement of the set, which represents members of set A which are not part of set B. see figure , here shaded region is shown, this shaded region indicates A - B.
here, A= {3, 6, 9, 12, 15, 18, 21},
B={4, 8, 12, 16, 20 },
C={2, 4, 6, 8, 10, 12, 14, 16},
D={5, 10, 15, 20}.
so, C - B = {2, 4, 6, 8, 10, 12, 14, 16} - {4, 8, 12, 16, 20}
here you can see that 4, 8, 12, 16 are present in both sets. so, C - B won't contain 4, 8, 12, 16 and will contain rest elements of C.
hence, C - B = {2, 6, 10, 14}.
here, A= {3, 6, 9, 12, 15, 18, 21},
B={4, 8, 12, 16, 20 },
C={2, 4, 6, 8, 10, 12, 14, 16},
D={5, 10, 15, 20}.
so, C - B = {2, 4, 6, 8, 10, 12, 14, 16} - {4, 8, 12, 16, 20}
here you can see that 4, 8, 12, 16 are present in both sets. so, C - B won't contain 4, 8, 12, 16 and will contain rest elements of C.
hence, C - B = {2, 6, 10, 14}.
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Solution :
Given C = { 2,4,6,8,10,12,14,16 }
B = { 4,8,12,16,20 }
C-B = {x:x€C and x doesn't belongs to B}
= { 2,4,6,8,10,12,14,16 } - { 4,8,12,16,20 }
= { 2 , 6, 10 , 14 }
••••
Given C = { 2,4,6,8,10,12,14,16 }
B = { 4,8,12,16,20 }
C-B = {x:x€C and x doesn't belongs to B}
= { 2,4,6,8,10,12,14,16 } - { 4,8,12,16,20 }
= { 2 , 6, 10 , 14 }
••••
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