lf a, a2 and 3a are in Ap , then the value of a is
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Solution:-
Since a, a - 2 and 3a are in AP,
∴ a − 2 − a = 3a − ( a − 2 )
⇒ − 2 = 2a + 2
⇒ 2a = − 4
⇒ a = − 2 (Answer)
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Answer:
Given Information:
a, a-2, 3a are in AP.
we know that
d2-d1 = d3-d2
(a-2)-a = 3a-(a-2)
-2 = 2a+2
-2-2 = 2a
-4 = 2a
a= -2
The value of a is -2
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