lf A ABC is isoscelesrrrith AB - AC = 7.5 cm
and BC : 9 cm (Fig). The heightAD from A to
BC,is6cm.Findthe areaof A ABC
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Answer:
ANSWER
In ΔABC, AD=6cm and BC=9cm
Area of triangle=
2
1
×base×height=
2
1
×BC×AD
=
2
1
×9×6=27 cm
2
Again, Area of triangle=
2
1
×base×height=
2
1
×AB×CE
⇒27=
2
1
×7.5×CE
⇒ CE=
7.5
27×2
⇒ CE=7.2cm
Thus, height from C to AB i.e., CE is 7.2cm.
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