Question

lf A and B are zeroes of x^2-5x+6, then find 3/4 (A^2-B^2)​

Answer 1

Answer:Since a and b are the zeros of the polynomial f(x)=x  

2

−5x+k

The standard quadratic equation is px  

2

+qx+r=0  

Then Sum of roots = −  

p

q

​  

 

and Product of roots =  

p

r

​  

 

Therefore,

a+b=5 and ab=k

Now, a−b=1

(a−b)  

2

=1

(a+b)  

2

−4ab=1

25−4k=1

24=4k

k=6

Answer 2

Answer:

Answer is :15/4

Step-by-step explanation:

x^2-5x+6=0

x^2-2x-3x+6=0

x(x-2)-3(x-2)=0

(x-2)(x-3)=0

(x-2)=0. or. (x-3)=0

x=2. or. x=3

So,A=3 and B=2

Now,

3/4(3^2-2^2)=3/4(9-4)=3/4*5=15/4

But,if u take A=2 and B=3 then ans comes negative.

I hope this will help u....