Question

lf a and Bita are roots of a quadratic equation x^2 + 4x +1, then the value of a^2- Bita^2 would be?" ​

Answer 1

Answer:

x² + 4x + 1

x(x+4) +1

(x+1)(x+4)

alpha = -1 and beta = -4

value of Alpha ² - beta² =

-1² - (-4²

1 - 16

= -15

Step-by-step explanation:

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Answer 2

$x ^{2} + 4x + 1 = 0 \\ \alpha + \beta = - 4 \\ \alpha \beta = 1 \\ ȯ \frac{1}{ { \alpha }^{2} } + \frac{1}{ { \beta }^{2} } \\ ȯ \frac{1}{ \alpha } + \frac{1}{ \beta } ^{2} - \frac{2}{ \alpha \beta } \\ ȯ \frac{ \alpha + \beta }{ \alpha \beta } ^{2} - \frac{2}{ \alpha \beta } \\ ȯ \frac{ - 4}{1} ^{2} - \frac{2}{1} \\ ȯ16 - 2 \\ ȯ14$