Question

lf a,b,c are three consecutive natural numbers then logb(1+ac)=

Answer 1

If a,b,c are three consecutive integers then log(1+ac)=
Let a=1st consecutive integer=a
a+1=2nd consecutive integer=b
a+2=3rd consecutive integer=c

Now, log(1 +ac) = log(1 + a(a+2))
= log(1 + a^2 + 2a)
= log(a^2 + 2a + 1)
= log(a^2 + a + a + 1)
= log({a+1} {a+1})
= log[(a + 1) ^2]
= log[(b) ^2]
=2log(b)

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