lf a pair of dice is thrown find probability of getting sum different from 8.
please give the correct answer otherwise your answer will be reported❤❤❤❤
Answers
Answer:
8 is
36
5
.
Step-by-step explanation:
The possible outcomes when two dice are thrown together are:
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).
Therefore, the number of possible outcomes when two dice are thrown is 36.
Now, the possible outcomes of getting a sum equal to 8 is {(2,6),(3,5),(4,4),(5,3),(6,2)}, which means the number of favourable outcome is 5.
Therefore, probability P of getting a sum equal to 8 is:
P=
36
5
Hence, the probability of getting a sum equal to 8 is
36
5
.
Answer:
0
the sum of the front and back side of a dice will always be 7
and the highest no. is 6 and getting 8is impossible