Question

lf A={x : x=3n,n€Z} and B={x : x=6n,n€Z} then find A U B and A intersection B

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Answer 1

Answer:

$\huge\star{\underline{{Hello!!}}}$

Step-by-step explanation:

Basically,the set A is the collection of numbers,which are divisible by 3.Similarly,the set B is the collection of numbers,which are divisible by 4.

So,A∩B is the collection of those positive numbers,which are divisible by both 3 and 4,ie which are divisible by LCM of 3 and 4 =12

So,A∩B={x:x=12n,n∈ℤ}

Answer 2

Step-by-step explanation:

A = {x : x = 3n, n ∈ Z} and B = {x : x = 6n, n ∈ Z}

It can be clearly seen that Set A consists of multiples of 3 and set B consists of multiples of 6. If a is a common multiple of both 3 and 6 = 3 * 6 * n = 18n where n is an integer.

Therefore,

A ∩ B = {x : x = 18n, n belongs to Z}

Hope it helps!