Math, asked by arifarizvi2813, 1 year ago

Lf ab = 5 and a-b =2, find the value of a³-b³

Answers

Answered by QUEEN007
0
Hey Friend ☺

ab = 5 .

a - b = 2 .

( a - b )^3 = a^3 - b^3 - 3ab( a - b )

》( 2 )^3 = a^3 - b^3 - 3( 5 )( 2 )

》8 = a^3 - b^3 - 30

》a^3 - b^3 = 30 + 8

》a^3 - b^3 = 38

Hope it helps you ..!!

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