Lf ab = 5 and a-b =2, find the value of a³-b³
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Hey Friend ☺
ab = 5 .
a - b = 2 .
( a - b )^3 = a^3 - b^3 - 3ab( a - b )
》( 2 )^3 = a^3 - b^3 - 3( 5 )( 2 )
》8 = a^3 - b^3 - 30
》a^3 - b^3 = 30 + 8
》a^3 - b^3 = 38
Hope it helps you ..!!
✌
ab = 5 .
a - b = 2 .
( a - b )^3 = a^3 - b^3 - 3ab( a - b )
》( 2 )^3 = a^3 - b^3 - 3( 5 )( 2 )
》8 = a^3 - b^3 - 30
》a^3 - b^3 = 30 + 8
》a^3 - b^3 = 38
Hope it helps you ..!!
✌
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