Question

lf alpha and beeta are the zeroes of the polynomial x2-6x+a ,find the value of a if 3alpha +2beeta =20. ​

Answer 1

please see the attachment

Answer 2

$\alpha + \beta = - \frac{b}{a}$

$\alpha + \beta = \frac{6}{ 1}$

Given:

$2( \alpha + \beta ) + \alpha = 20$

$(2 \times 6) + \alpha = 20$

$\alpha = 8$

$f( \alpha ) = 0$

$64 - 48 + a = 0$

Therefore,

$a = - 16$