Question

lf alpha and beta zeros of polynomials is x square -3x+2 find the polynomial whose zeros are 3alpha and 3beta​

Answer 1

Answer:

$\alpha + \beta = - \frac{b}{a} \\ \alpha + \beta = 3 \\ so \: 3 \alpha + 3 \beta = 3( \alpha + \beta ) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3 \times 3 = 9 \\ product \: ofthe \: zeroes \: = 2 \\ \alpha \beta = 2 \\ 3 \alpha \times 3 \beta = 9 \times 2 = 18 \\ f(x) = {x}^{2} - 9x + 2$

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