Question

lf an object's velocity changes from 25 meters per second to 15 meters per second in 2.0 seconds, the magnitude of the object's acceleration is !


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Answer 1

$\huge\green{\tt Correct \: Question :-}$

$\implies$lf an object's velocity changes from 25 m/s to 15 m/s in 2.0 seconds the magnitude of the object's acceleration is

$\huge\blue{\tt Given :-}$

• lf an object's velocity changes from 25 m/s to 15 m/s in 2.0 seconds

$\huge\orange{\tt To \: Find :-}$

• The magnitude of the object's acceleration

$\huge\pink{\tt Solution :-}$

We have,

• Final Velocity(v)= 15 m/s
• Initial Velocity(u) = 25 m/s
• Time taken(t) = 2.0 s = 2 s

We know that,

$\boxed{\tt a = \dfrac{v - u}{t}}$

Where,

• a = Acceleration
• v = Final Velocity
• u = Initial Velocity
• t = Time taken

Substituting the values we get,

$:\implies\tt a = \dfrac{15-25}{2}$

$:\implies\tt a = \dfrac{\cancel{-10}}{\cancel2}$

$:\implies\gray{\tt a = - 5 \: m/s^{2}}$

We also know that,

$\boxed{\tt Negative \: sign \: represents \: that \: object \: is \: slowing \: down}$

$\therefore\bf The \: magnitude \: of \: the \: object's \: acceleration \: is \: 5 \: m/s^{2}$

Answer 2

Given:

An object's velocity changes from 25 meters per second to 15 meters per second in 2.0 seconds.

To find:

Acceleration of the object?

Calculation:

• Acceleration is a vector quantity characterized by the rate of change of velocity with respect to time.

Applying EQUATIONS OF KINEMATICS:

$\rm \: v = u + at$

$\rm\implies \: a = \dfrac{v - u}{t}$

$\rm \implies \: a = \dfrac{15 - 25}{2}$

$\rm \implies \: a = \dfrac{ - 10}{2}$

$\rm \implies \: a = - 5 \: m {s}^{ - 2}$

So , acceleration of object is -5 m/s².

• Please note that : '-' sign of acceleration denotes that the direction of acceleration is opposite to direction of velocity.