Question

lf an object's velocity changes from 25 meters per second to 15 meters per second in 2.0 seconds, the magnitude of the object's acceleration is !

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Answer 1

Answer :

• The magnitude of the acceleration of the object is (-5) m/s².

Explanation :

Given :

• Initial velocity of the object,u = 25 m/s
• Final velocity of the object, v = 15 m/s
• Time taken, t = 2 s

To find :

• Magnitude of the acceleration produced by the object, a = ?

Knowledge required :

First equation of motion :

⠀⠀⠀⠀⠀⠀⠀⠀⠀v = u + at⠀

Where,

• v = Final velocity of the object.
• u = Initial velocity of the object.
• a = Acceleration of the object.
• t = Time taken.

Solution :

By using the first equation of motion and substituting the values in it, we get :

⠀⠀⠀=> v = u + at

⠀⠀⠀=> 15 = 25 + a(2)

⠀⠀⠀=> 15 - 25 = 2a

⠀⠀⠀=> -10 = 2a

⠀⠀⠀=> -10/2 = a

⠀⠀⠀=> -5 = a

⠀⠀⠀⠀⠀∴ a = (-5) m/s²

Therefore,

• The acceleration produced by the body is -5 m/s².

Answer 2

Answer:

✠ Given :-

• An object velocity changes from 25 m/s to 15 m/s in 2 seconds.

✠ To Find :-

• What is the magnitude of the object acceleration.

✠ Formula Required :-

✯ v = u + at ✯

【 where, v = Final Velocity, u = Initial Velocity, a = Acceleration, t = Time 】

✠ Solution :-

Given in the question :-

★ u = 25 m/s

★ v = 15 m/s

★ t = 2 seconds

ATQ :-

⇒ 15 = 25 + a × 2

⇒ 15 = 25 + 2a

⇒ - 2a = 25 - 15

⇒ - 2a = 10

⇒ a = $\dfrac{10}{-\: 2}$

➠ a = - 5 m/s

∴ The magnitude of the object acceleration is - 5 m/s.