Question

lf cosec theta = 4 and cot theta = √3 k.K=?

Answer 1

Gn that

$\csc(x) = 4$
But ,

${ \csc(x) }^{2} - { \cot(x) }^{2} = 1$
ie


$16 - 1 = { \cot(x) }^{2}$
ie


${ \cot(x) }^{2} = 15$
ie
$\cot(x) = \sqrt{15} = \sqrt{3} \times \sqrt{5}$
Therefore K=
$\sqrt{5}$