Question

lf distance between to points (k,2) and (3,4) is 8 then k=​

Answer 1

Answer:

we have distance formula=

\sqrt{(x1 - x2)2 + (y1 - y2)2}

=>

\sqrt{(k - 3)2 + (2 - 4)2} = 8

=> k^2+9-6k+ 4= 8

=> k^2 -6k+13 =8

=> k^2 -6k +5=0

=> k^2-5k -k+5=0

=> k(k-5) -1(k-5)=0

=> (k-1) (k-5)=0

=> k-1=0 or, k-5=0

=> k=1 or k = 5.

Thank me and follow ❤️❤️