Question

lf loga 32 = 5; then a :?​

Answer 1

Answer:

a= 2

Step-by-step explanation:

Given,

log 32 base a = 5

= let's take a =2

= log 32 base 2

=log 2^5 base 2^1

=5/1 log 2 base 2

= 5 (1)

=5

a = 2

Answer 2

Answer:

$if \: log \: x \: (32) = 5 \: then \: x {}^{5} = x \: log \: x \: (32) = 32.$

$so \: \: \: x = \sqrt[5]{32 \: = \sqrt[5]{25 = 2} }$

Step-by-step explanation:

Alternatively, use the change of base formula:

$5 \: log \: x(32) = in \ \times \frac{in \: (32)}{in \: (x)}$

$in(x) \frac{in \: (32)}{5 } = in \: \sqrt[5]{32} = in \: ( \sqrt[5]{2 {}^{2} }$

$(answer) \: in \: (2)$

i hope answer is helpful to us