Question

lf one root of the quadratic equation 2×2+kx+4=0is2 then then the other root is​

Answer 1

Answer:

Value of B is 1

Step-by-step explanation:

Let A and B be the roots of quadratic equation 2x²+kx+4=0

in such a way that A=2

Here A=2 B=k and C=4

Then according to the question sum of the roots:

A+B= (-B/A)

A+B= (-B/A)or 2+B= (–k/2)

A+B= (-B/A)or 2+B= (–k/2)or B= (-k/2)–2

A+B= (-B/A)or 2+B= (–k/2)or B= (-k/2)–2orB=(–k–4)/2

And the product of roots:

A×B=C/A

A×B=C/Aor4/2

A×B=C/Aor4/2orB=2

putting the value of B=(–k–4)/2 in above:

2×(–k–4)/2=2

2×(–k–4)/2=2or (–k/–4)=2

2×(–k–4)/2=2or (–k/–4)=2or k= (–4–2)

2×(–k–4)/2=2or (–k/–4)=2or k= (–4–2)or k= (–6)

putting the value of k in B=(–k–4)/2:

B= (–(6)–4)/2

B= (–(6)–4)/2or B=(6–4)/2

B= (–(6)–4)/2or B=(6–4)/2or B=2/2

B= (–(6)–4)/2or B=(6–4)/2or B=2/2orB=1

Therefore, value of root be B=1

Hope!This help you friend.....