Question

lf p=1 and q= -2 are root of a quadratic equation ,then quadratic equation will be_________​

Answer 1

Answer:

$x^{2} +x-2 =0$ is the quadratic equation

Step-by-step explanation:

We know that, if p and q are the roots of the equation then,

the quadratic equation is represented by $x^{2} -(p+q)x+pq=0$

here p=1 and q =-2

substituting p and q in equation, we get $x^{2} +x-2 =0$

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Answer 2

Step-by-step explanation:

Given :-

p = 1 and q = -2

To find:-

Find the Quadratic equation whose roots are p = 1 and q = -2 ?

Solution:-

Given roots are :

p = 1 and

q = -2

We know that

If α and β are the roots then the Quadratic equation is x^2-(α+ β)x +αβ = 0

The quardratic equation whose roots are p and q is x^2-(p+q)x+pq=0

=> x^2- (1+(-2))x+(1)(-2) = 0

=> x^2-(1-2)x+(-2) = 0

=> x^2-(-1)x-2 = 0

=> x^2+x-2 = 0

Answer:-

The required quardratic equation is x^2+x-2 = 0

Used formula:-

• If α and β are the roots then the Quadratic equation is x^2-(α+ β)x +αβ = 0