Question

lf 'p-5' gives 12; Find the value of p​

Answer 1

Answer:

$(p - 12) {x}^{2} + 2(p - 12)x + 2 = 0$

Have two real and equal roots...

So,

$d = {b}^{2} - 4ac = 0$

Here,

$b = 2(p - 12)$

$a = (p - 12)$

$c = 2$

Now,

$= \geqslant d =2(p - 12)^{2} - 4.2(p - 12) = 0$

$= 4(p - 12) ^{2} - 2(p - 12) = 0$

$= (p - 12) ^{2} - 2 (p - 12) = 0$

$= (p - 12)(p - 12 - 2) = 0$

$= (p - 12)(p - 14 )= 0$

Hence,

Value of p = 12, 14

✨HoPe iT HeLpS

✨ AkRiTi

Answer 2

Answer:

Bro naaan ungalukku neraya thanks sollirukan!

Step-by-step explanation:

Nanum tamil than bro

Unga pointsa waste panrannu nenacha sorry bro

Illa paravalana intha answerku thanks sollunga

please

En per surya