lf p(x) = ax³ -3x²+5x- 36 has (x-4) as it's factor, then the value of a is
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Answer:
ax³-3x²+5x-36=0--------------------(x-4,X=4)
a×64-3×16+5×4-36=0
64a-48+20-36=0
64a+20-84=0
64a=64
a=1Answer
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