Question

lf p²x² - q² =0 , then x=?
a)+q/p
b)+p/q
c)p
d)q​

Answer 1

hope it will help you.....

a option

Answer 2

Answer:

$\huge{\red{\bf{\mathfrak{Answer}}}}$

lf p²x² - q² =0 , then x=?

a)+q/p✔✔✔

b)+p/q

c)p

d)q

$\huge{\purple{\bf{\mathfrak{solution}}}}$

${p}^{2} {x}^{2} - {q}^{2} = 0 \\ \\ {p}^{2} \times ( \frac{ {q}^{2} }{ {p}^{2} } ) - {q}^{2} = 0 \\ \\ {q}^{2} - {q}^{2} = 0$