Question

lf PQ equal to 8 cms , QR equal to 7.5 cms and angle PQR equal to 85 degree . how to construct it

Answer 1

Answer:.

Step-by-step explanation:firstly take PQ 8cm at base and then by using protector take 85degree on angle pQR then take distance of 7.5cm on RQ and construct triangle

Answer 2

Therefore $PQR$ is the required triangle.

Step-by-step explanation:

Given;

Construct a triangle $PQR$ where $PQ=8$cm , $QR=7.5$ cm and $\angle PQR=85$ degree

Following steps:

• Draw a line $PQ$ which is equal to $8$ cm

• At point $Q$, draw an angle $85$ degree and extend the line like as $QS$

• Take a measurement $7.5$cm and cut the line $QS$ from point $P$

Now $PQR$ is the required triangle.