lf sec theta +tan theta=p,then find the value of sec theta-tan theta
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Answer: 1/p
Step-by-step explanation:
secΘ + tanΘ = p -------(1)
We know that,
sec²Θ+tan²Θ= 1
(secΘ+tanΘ)(secΘ-tanΘ) -----------using a² - b² = ( a + b )( a - b )
p(secΘ-tanΘ) = 1 -------- From (1)
secΘ-tanΘ= 1/p
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