Question

lf sum of zeroes of 3x^2- (2k+1)x - k -5 is equal to the product of the zeroes, find k.

Answer 1

Answer:

-2

Step-by-step explanation:

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Answer 2

Sum of zeroes = Product of zeroes

-b/a = c/a

-b = c

=> 2k + 1 = -k - 5

=> 3k = -6

=> k = -2