Math, asked by JAIDEVILMAN42, 9 months ago

lf sum of zeroes of 3x^2- (2k+1)x - k -5 is equal to the product of the zeroes, find k.

Answers

Answered by paidilokesh295
5

Answer:

-2

Step-by-step explanation:

Hope this helps you

Mark as Brainliest answer please

Attachments:
Answered by Anonymous
0

Sum of zeroes = Product of zeroes

-b/a = c/a

-b = c

=> 2k + 1 = -k - 5

=> 3k = -6

=> k = -2

Similar questions