Physics, asked by sakshism0707, 1 month ago

lf sx=t^2+t+4m and sy=4tm at t=3s the magnitude of displacement is​

Answers

Answered by kumarumeshbind
1

sx= 9+3+4= 16

sy= 12

hence displacement = √(16^2 +12^2)= √(256+144)

= √ ( 398)=20 meter estimated

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