Question

lf tan alpha=1/2,tab beta=1/3 then (alpha+beta)=
1)30degrees
2) 60degrees
3)45degrees
4)0degrees​

Answer 1

Given

tan alpha = 1/2

tan beta = 1/3

we know that

Tan(A+B) = tanA + tanB /1-tanAtanB

that implies tan(alpha+beta)=tan alpha + tan beta/1-tan alpha tan beta =1/2+1/3/1-(1/2)(1/3)=5/5 = 1

tan(alpha+beta)=1

that implies (alpha+beta)= 45 degrees

Answer=3) 45 degrees