Question

lf
$x + \frac{1}{x} = 11 \: find \: the \: value \: of \: {x}^{2} + \frac{1}{ {x}^{2} }$
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Answer 1

Step-by-step explanation:

${x}^{2} + \frac{1}{ {x}^{2} }$

$= ( {x + \frac{1}{x}) }^{2} - 2 \times x \times \frac{1}{x}$

$= ( {11)}^{2} - 2$

$= 121- 2$

$= 119$