Question

lf the altitude from two vertices of a triangle to the opposite sides are equal. prove thathe triangle is isosceles​

Answer 1

hope it will help you...

Answer 2

Answer:

....

△ABC is an isosceles tangent as two sides are equal to each other

In △ABE and △ACF

∠AEB=∠AFC (90⁰ each)

∠BAE=∠CAF (common angle)

∠ABE=∠ACF using angle sum property

BE=CF

⇒ △ABE≅△ACF

⇒ AB=AC

∴ △ABC is an isosceles tangent as two sides are equal to each other