Question

lf the current supplied by the
battery is 2A in 0.02s. Calculate the
potential difference between the
ends of the battery if energy given
by it 60J.​

Answer 1

Answer:

$\bigstar{\bold{Potential\:difference=1500\:V}}$

Explanation:

$\Large{\underline{\sf{Given:}}}$

• Current supplied = 2 A
• Time taken = 0.02 s
• Heat energy = 60 J

$\Large{\underline{\sf{To\:Find:}}}$

• Potential difference

$\Large{\underline{\sf{Solution:}}}$

➜ Here we have to first find the resistance of the circuit.

➜ By Joule's law we know that,

   H = I²R T

    where H = heat energy

    I = current

    R = resistance

    T = time taken

➜ Substituting the data,

    60 = 2² × R × 0.02

    0.08 R = 60

     R = 60/0.08

     R = 750 Ω

➜ Hence resistance of the circuit is 750 Ω.

➜ Now we have to find the potential difference of the circuit.

➜ By Ohm's law we  know that,

   V = I R

    where V = potential difference

    I = current

    R = resistance

➜ Substitute the data,

    V = 2 × 750  

   V = 1500 V

➜ Hence the potential difference across the circuit is 1500 V.

    $\boxed{\bold{Potential\:difference=1500\:V}}$

$\Large{\underline{\sf{Notes:}}}$

➜ By Ohm's law, the potential difference across the two ends of a conductor is directly proportional to the amount of current flowing through it.

V = I R

➜ By Joule's law, heat energy produced in a circuit is directly proportional to the square of the current flowing through it, resistance and time for which the current flows.

H = I² R T