Question

lf the sum of the zeroes of the polynomial p(x)=(k^2-14)x^2-2x-12 is 1 ,then one of the values of k is
a) root 14
b)-14
c)2
d)-4

Answer 1

Hi friend!!

Given,

p(x) = (k²-14)x² - 2x - 12

Sum of zeroes = -b/a = -x coefficient/x² coefficient

1 = -(-2)/k²-14

1 = 2/(k²-14)

k²-14 = 2

k² = 2+14

k² = 16

k = √16

k = ±4

k = -4,+4

Option d is correct!

Answer 2

sum of zeroes = 1

-x coefficient/x² coefficient = 1

2/k²-14 = 1

2 = k²-14

k² = 16

k = √16

k = -4

d is answer

:-)