Science, asked by arfeena13, 8 months ago

lf two gases of molecular weight of m1 and m2 at temp t1 and t 2,t1m2=t2m1.then which property has the same magnitude for both gases

Answers

Answered by neetupapolaparihar

1

Answer:

√M2 : √M1

Explanation:

Root mean square velocity

Vrms=√3RT/M

=√3P/ρ

R = Universal gas constant

M = molar mass

P = pressure due to gas

ρ= density

Vrms ∝ 1/√M

∴v1 / v2 = √m2 / √m1

Ans : √M2:√M1

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