Question

lf x/y = 2/3 then 2x²+3y²/2x²- 3y²=?​

Answer 1

Answer:

x=2 y=3

2*2*2+3*3*3/2*2*2-3*3*3

8+27/8-27

take LCM as 8

then it will come as (64/8+27/8)-27

91/8-27

take LCM as 8

91/8 - 216/8

=-195/8 = 24.375

marke as brainliest answer

Answer 2

By Using the concept of Componendo-Dividendo,

$\dfrac{a}{b} = \dfrac{c}{d}$

$\dfrac{a + b}{a - b} = \dfrac{c + d}{c - d}$

So, We find the value of

$\left( \dfrac{x}{y} \right) ^{2} = \dfrac{4}{9}$

$= \dfrac{2 {x}^{2} }{3 {y}^{2} } = \dfrac{8}{27}$

$\dfrac{2x^2+3y^2}{2x^2-3y^2} = \dfrac{8+27}{8-27}$

$\dfrac{2x^2+3y^2}{2x^2-3y^2} = \dfrac{35}{-19}$

$= \boxed{ - \dfrac{ 35}{ 19} }$