Math, asked by anwarsaadiq789, 8 hours ago

lfactorise 12(x²+7)-8(x²+7)(2x-1)-15(2x-1)​

Answers

Answered by Mudit7260
1

Step-by-step explanation:

12(x

2

+7x)

2

−8(x

2

+7x)(2x−1)−15(2x−1)

2

=12(x

2

+7x)

2

−18(x

2

+7x)(2x−1)+10(x

2

+7x)(2x−1)

−15(2x−1)

2

=6(x

2

+7x)[2(x

2

+7x)−3(2x−1)]+

5(2x−1)[2(x

2

+7x)+3(2x−1)]

=[2(x

2

+7x)−3(2x−1)][6(x

2

+7x)+5(2x−1)]

=[2x

2

+14x−6x+3][6x

2

+42x+10x−5]

=(2x

2

+8x+3)(6x

2

+52x−5)

∴12(x

2

+7x

2

)

2

−8(x

2

+7x)(2x−1)−15(2x−1)

2

=[2(x

2

+7x)−3(2x−1)][6(x

2

+7x)+5(2x−1)]

=(2x

2

+8x+3)(6x

2

+52x−5)

Answered by amritjha7552
0

Answer:

take +7and2x-1 as common in both and continue:-

(x²+7)12-8. (2x-1)1-15

(x²+7)4. (2x-1)14

Similar questions