Question

lfind the breath of a rectangle if it's perimeter is (3a+4b-2c) unit length is (4a-2c)​

Answer 1

Answer:

perimeter= l+b

l= 4a-2c

perimeter=3a+4b-2c

(4a-2c)+b=3a+4b-2c

b=3a+4b-2c-(4a-2c)

b=3a+4b-2c-4a+2c

b=3a-4a+4b

b= -a+4b

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Answer 2

Answer:

2b+c-(5/2)a

Step-by-step explanation:

Given, perimeter=3a+4b-2c

length=4a-2c

Let, breadth=x

We know that, perimeter of a rectangle =2(length+breadth)

3a+4b-2c=2(4a-2c+x)

3a+4b-2c=8a-4c+2x

5a-4b-2c+2x=0

2x=4b+2c-5a

x=2b+c-(5/2)a

Therefore,breadth of the rectangle is 2b+c-(5/2)a

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