CBSE BOARD X, asked by jhas6261, 9 months ago

lFind the Centroid of the triangle whose vertices are x(4,-1),y(1,2)&z(3,-1).

Please solve properly and Full solution is needed.

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Answers

Answered by Anonymous
35

\large{\red{\bold{\underline{Given:}}}}

\sf \: Coordinates \: of \: the \: vertices \: are: \:  x(4,-1), \: y(1,2) \: and \: z(3,-1)

\large{\green{\bold{\underline{To \: Find:}}}}

 \sf \: Centroid \: of \: the \: triangle

\large{\blue{\bold{\underline{Formula \: Used:}}}} \\  \\ \sf \:Coordinates \: of \:Centroid =   \: (\frac{x_{1} + x_{2} + x_{3}}{3} ),( \frac{y_{1} + y_{2} + y_{3}}{3})

\large{\red{\bold{\underline{Solution:}}}} \\  \\  \: \sf \: On \: considering \: the \: respective \: coordinates \: as :

 \sf \: x(4,-1) \: \rightarrow \: (x_{1}, y_{1}) \\ \\\sf \: y(1,2) \: \rightarrow \: (x_{2}, y_{2})  \\  \\  \sf \: z(3,-1) \: \rightarrow \: (x_{3}, y_{3})

\large{\pink{\bold{\underline{Now:}}}} \\ \\ \rightarrow \: \sf \: Centroid = ( \frac{4 + 1 + 3}{3}) ,( \frac{-1 + 2 + (-1)}{3} ) \\ \\  \rightarrow \sf \: Centroid = ( \frac{5 + 3}{3}) , (\frac{-2 + 2}{3} ) \\  \\ \rightarrow \sf \: Centroid = ( \frac{8}{3} ),( \frac{0}{3} ) \\  \\ \rightarrow \sf \: Centroid = (2.6,0)

\large{\orange{\bold{\underline{Therefore:}}}} \\  \\  \sf \: The \: coordinates \: of \: Centroid \: of \: the \: triangle \\ \sf \: is \: (2.6,0).

Answered by Anonymous
35

Answer:

Step 1: Identify the coordinates of each vertex. Step 2: Add all the x values from the three vertices coordinates and divide by 3. Step 3: Add all the y values from the three vertices coordinates and divide by 3. Step 4: Determine the centroid coordinate.

Explanation:

use this formula

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