lfs the angle between two tangent drawn from an external point P to a circle of a radius a and centre o, is 60 degree , then find the length of op
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Radius = a
Let the tangents be AP and BP
Then angle APB = 60 degrees
Construction: Join OP
Now, in triangle OPA
Angle PAO = 90 degrees
Angle POA = 180 - (90 + 30)
= 60 degrees
Now, in triangle
cos O = B/H
cos O = OA/OP
cos 30 = a/H
√3/2 = a/H
√3H = 2a
OP = (2a/√3) u
jashmeet47:
thank you for helping me
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