Question

लगाउनुहोस्। A and B can do a piece of work in 18 days and 24 days respectively. A and B both worked together and after some days A left the work. B finished the remaining work in 3 days. How long did A worked with B? Find it.​

Answer 1

Step-by-step explanation:

16 days

(A + B)’s 1 day’s work $latex = \frac{1}{18}&s=1$

(B + C)’s 1 day’s work $latex = \frac{1}{24}&s=1$

(C + A)’s 1 day’s work $latex = \frac{1}{36}&s=1$

On adding,

2(A + B + C)’s 1 day’s work $latex = \frac{1}{18}+\frac{1}{24}+\frac{1}{36} = \frac{4+3+2}{72} = \frac{1}{8}&s=1$

∴ (A + B + C)’s 1 day’s work $latex = \frac{1}{16}&s=1$

∴ A, B and C together will complete the work in 16 days.

Hence option [D] is correct answer.