Question

Li and a proton are accelerated by the same potential, their
de Broglie wavelengths lLi and lₚ have the ratio (assume
mLi = 9mₚ )
(a) 1 : 2 (b) 1 : 4
(c) 1 : 1 (d) 1: 3 3

Answer 1

Li and a proton are accelerated by the same potential, then their

de Broglie wavelengths λ$_{Li}$ and λₚ have the ratio of 1: 3

- the de broglie wavelength of atoms can be given by the formula

    λ = h/$\sqrt{2mK}$

- here, they are accelerated by the same potential, so that means λ $\alpha$ 1/$\sqrt{m}$

- so  λ$_{Li}$/λₚ = $\sqrt{mp/mLi}$

                 = $\sqrt{1/9}$

                 = 1/3

- Thus the answer is λ$_{Li}$ : λₚ = 1:3

- so the correct option is (d)

-

Answer 2

Answer:

hope the above answer is correct