Question

Li is going to paint a door that measures 195 cm by 74 cm.
He is going to give it two layers of paint on each side.
One tin of paint covers 5 m².
How many tins of paint does Li need to buy?
Show how to check your answer.​

Answer 1

Answer:

Hii user......

Good morning.....

Here is your answer.....

The length of door is = 197 cm

And the breath of door is = 74 cm

Now first find its area =

Area= L× B

So 197× 74 = 14578 cm

Now let change the area in m by cm....

1 m=100cm

So devide 14578 by 100 to change cm in meter ...

So we get = 145.78 m*2

Now if one tin covers 5m*2 then devide 145.78 m *2 by 5m*2

29.156 tins ...for one layer....

So multiply 28.156 tins×2

58.312 tins are needed for the duble layer of paint of door ......

Hope this helps you mate.....✍️

Radhe radhe ✍️

Jai Shri Krishna ✍️

Step-by-step explanation:

Answer 2

Answer:

2 tins. The answer above of 58.312 is incorrect .

Step-by-step explanation:

To make it easier to grasp and to avoid dealing with complex conversions later on, it is advised to convert numbers into more managable sizes.

In this case, let us convert the dimensions of the door from cm into m

195cm ---> (195/100)m

=1.95m

74cm--->(74/100)m

=0.74m

Once you've obtained the answer, multiply them by each other to get the area of one side of the door. (Area = Length x Width )

1.95m x 0.74m =$1.443m^{2}$

Now, the question states that he is going to give it two layers of paint on each side. This means that Li coats the front side of the door with 2 layers (Twice) , and the back side of the door with another 2 layers (Twice).

This results in our general equation to be ,

2 x ( $1.443m^{2}$ x 2)

l                        l                      

l                        l

l                        This 2 refers two the number of coats of paint on one side.

l

l

This 2 refers two the number of sides on the door (Front and Back)

2 x ($1.443m^{2}$ x 2) = 5.772$m^{2}$

Therefore, the total area of paint needed to cover both sides of the door with two layers of paint is 5.772$m^{2}$.

As one tin of paint only covers 5$\\m^{2}$ , To find the total number of tins needed, Divide the total area of the door by the total area that 1 tin of paint is able to cover.

5.772$\\m^{2}$÷$5m^{2}$

= 1.1544 tins.

It is impossible to buy 1.1544 tins of paint therefore you would need 2 tins of paint. Buying 1 tin would not be enough to cover 5.772$m^{2}$ of the door.

Hope this helps.